How many atoms are in 5 moles of sulfur?
1 mole is defined as Avogadro’s number (6.02*10^23) of something. So 1 mole of sulfur (or any other element) is 6.02*10^23 atoms of sulfur. 5 moles is just 5 times that amount.
How many grams are in 5.0 moles?
Therefore, 5 moles × 32.0 g/mol = 160 grams is the mass (m) when there are 5 moles of O2 .
Are there in 5.5 mole of sulphur?
Answer: So 1 mole of sulfur (or any other element) is 6.02*10^23 atoms of sulfur. 5 moles is just 5 times that amount.
How many grams are in 2 moles of sulfur?
The mass of a mole of sulfur atoms is 32.06⋅g .
How many atoms are in 5 moles?
Avogadro’s number: the amount of atoms in 1 mole of carbon 12 is 6.022 x 10^23. So if you have 5 mole, you have: 5 x (6.022 x 10^23) = 3.011 x 10^24 atoms.
How many atoms are in 1 gram of sulfur?
Explanation: Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1 . Because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.
How many grams are in 4.3 moles of sulfur?
That means that one mole of sulfur weighs 32.06 grams (32.06 g/mol). Based on that information, to convert 4.3 moles of sulfur to grams, we multiply 4.3 moles of sulfur by 32.06.
How many mL is 5 grams?
Grams to mL conversions (water)
|Grams to mL||Grams to mL|
|3 grams = 3 mL||150 grams = 150 mL|
|4 grams = 4 mL||200 grams = 200 mL|
|5 grams = 5 mL||250 grams = 250 mL|
|6 grams = 6 mL||300 grams = 300 mL|
Is moles and grams the same?
The mass of a mole of substance is called the molar mass of that substance. The molar mass is used to convert grams of a substance to moles and is used often in chemistry.
Applications of the Mole.
|Known Information||Multiply By||Result|
|Mass of substance (g)||1/ Molar mass (mol/g)||Moles of substance|
How many atoms or molecules are in 5.0 moles of O?
Hence, number of moles of Oxygen in 5 Moles of CO = 5. The number of oxygen atoms present can be obtained by multiplying the moles of oxygen by Avogadro’s Number. So, number of oxygen atoms present = 5 x ( 6.023 x 10^23 ) = 30.115 x 10^23 nos.