How many grams are in a mole of silver nitrate?

What is the mole of AgNO3?

you find moles of AgNO3. That is 0.0132 g AgNO3 x 1 mol AgNO3/169.9 g = 7.77×10-5 moles. Since there is 1 mole Ag and 1 mole NO3 per mole of AgNO3, this is also the number of moles of Ag+ and NO3- ions.

How do you calculate 1 mole of AgNO3?

So in order to calculate the number of moles of any substance present in the sample, we simply divide the given weight of the substance by its molar mass. Where ‘n’ is the number of moles, ‘m’ is the given mass and ‘M’ is the molar mass.

How much is a mole of silver?

This mass is given by the atomic weight of the chemical unit that makes up that substance in atomic mass units (amu). For example, silver has an atomic weight of 107.8682 amu, so one mole of silver has a mass of 107.8682 grams.

How many grams does nitrate have?

The reason for this conversion is that nitrate molecule weighs 62 grams per mole; the nitrogen content of nitrate is 22.5% of the total weight of the molecule.

How many moles of silver nitrate were added to the reaction?

1 Approved Answer

Answer: Generally, density of silver nitrate solution is 4.35 g/mL. So, 200mL silver nitrate solution contained 200*4.35 gm = 870gm = 870/169.87 mol = 5.12 moles of AgNO3 solution was added initially.

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How many moles are in 2.58 g of silver nitrate?

1 Expert Answer

1) (2.58 g AgNO3) * (1 mole AgNO3 / 169.9 g AgNO3) = 0.0152 mole AgNO3.

How many particles are in a gram?

1.4.

The definition of Avogadro’s number of 6.022 × 1023/mole is the number of atoms or molecules per one gram atomic weight.

How much atoms are in a mole?

The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro’s Number (6.0221421 x 1023).