How do you find the moles of magnesium oxide?
Calculating the mass of reactants
- Magnesium reacts with oxygen to produce magnesium oxide:
- 2Mg(s) + O2(g) 2MgO(s)
- Calculate the mass of magnesium needed to produce 12.1g of magnesium oxide.
- (Relative masses: Mg = 24.3, MgO = 40.3)
- number of moles of MgO =
- =
- = 0.300 mol.
How many moles are in magnesium?
The relative masses of each element can be found on the periodic table. For example, one atom of magnesium weighs 24.31 amu (atomic mass units). However, one mole of magnesium weighs 24.31 g. (Moles were planned that way!)
How many grams are in one mole of magnesium oxide?
Correct answer:
The molar mass of MgO is 40.3 grams. The molar mass of magnesium is 24.3 grams.
How many magnesium atoms are there in magnesium oxide?
For example, magnesium oxide is made up of two elements, magnesium and oxygen. Its formula is MgO. This shows that it has one atom of magnesium for every one atom of oxygen.
How many grams of magnesium oxide MgO are in 12.2 moles of magnesium oxide?
How many moles of water, H2O are needed if you have 82 grams of magnesium oxide, MgO to produce magnesium hydroxide, Mg(OH)2? MgO + H2O + Mg(OH)2 olimo Mg ol mol H2O2. 03. 139 gk /?
How do you calculate the number of moles of magnesium?
Example calculation:
- Mass magnesium = 2.39 g.
- Mass magnesium oxide = 3.78 g.
- So mass oxygen = 1.39 g.
- Number moles Mg = 2.39/24 = 0.0995.
- Number moles O = 1.39/16 = 0.0868.
- Divide by the smallest to give the ratio aproximately 1 Mg : 1 O.
- This would suggest a formula of MgO, which is the correct formula.