# Quick Answer: How many moles are required to neutralize?

Contents

## How do you calculate moles needed to neutralize?

So, the solution will be neutralized when the number of moles of H+ equals the number of moles of OH.

1. Step 1: Calculate the number of moles of OH.
2. Molarity = moles/volume.
3. moles = Molarity x Volume.
4. moles OH = 0.02 M/100 milliliters.
5. moles OH = 0.02 M/0.1 liters.
6. moles OH = 0.002 moles.

## What is the neutralization formula?

Let’s see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCl → H2O and NaCl. Now let’s break this reaction down into two parts to see how each product forms.

## How do you calculate moles of HCl neutralized by antacids?

Therefore, the number of moles of HCl that reacted with the antacid should be equal to the total number of moles of HCl minus the number of moles of excess HCl. Take this amount and divide by the mass of the sample and you have your acid neutralizing capacity.

## How many moles of H2SO4 are needed to exactly neutralize 5.0 moles NaOH?

Therefore it would take . 25 moles of sulfuric acid to react with . 5 moles of sodium hydroxide.

THIS IS IMPORTANT:  Your question: Can water give you pimples?

## How many moles of H2SO4 are needed to completely neutralize?

0.10 moles or 9.8 grams.

## Why are 3 moles of sodium hydroxide required for every 1 mole of citric acid?

It is produced as a crystalline solid, either anhydrous, or as a monohydrate, and is available in either form at low cost. The solid monohydrate loses water below 100 °C when heated, forming the anhydrous solid, which melts at 156 °C, and decomposes at 175 °C.

## How much h3po4 is needed to neutralize?

Therefore, 0.1622 ml of 75% phosphoric acid is needed to neutralize 1 liter of water with an alkalinity of 270 mg CaC03Aiter. To determine the amount of acid required per gallon, multiply the amount of acid required per liter by 3.785. In our example, 0.61 ml of phosphoric acid would be required per gallon of water.