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## How do you find the volume of carbon dioxide at STP?

Let us now determine the volume of carbon dioxide present in the reaction using the ideal gas equation i.e. **[PV = nRT]** where n is the number of moles of gas and R is the gas constant. The volume of carbon dioxide gas evolved at S.T.P. by heating 7.3 gm of [Mg{(HC{O_3})_2}] will be 2240ml.

## What is one mole of CO2 gas at STP?

Standard temperature and pressure (STP) is defined as 0°C (273.15 K) and 1 atm pressure. The molar volume of a gas is the volume of one mole of a gas at STP. At STP, one mole (6.02 × 10 ^{23}**representative particles**) of any gas occupies a volume of 22.4 L ( Figure below ).

## How many moles are in STP?

Molar volume at STP can be used to convert from moles to gas volume and from gas volume to moles. The equality of **1mol=22.4L** is the basis for the conversion factor.

## How do you find volume at STP?

It can be written as: **V = nRT/P**. “P” is pressure, “V” is volume, n is the number of moles of a gas, “R” is the molar gas constant and “T” is temperature. Record the molar gas constant “R”. R = 8.314472 J/mole x K.

## What volume does CO2 release at STP?

The volume of carbon dioxide obtained at STP is **$1.12,litre$**. So, the correct answer is Option B . Note: We must remember that the equal volume of all gases at the standard temperature and pressure comprises the same number of particles.

## What gas occupies 22.4 at STP?

A mole of any gas occupies 22.4 L at standard temperature and pressure (0°C and 1 atm). Figure below illustrates how molar volume can be seen when comparing different gases. Samples of helium (He), nitrogen (N_{2}), and **methane (CH _{4})** are at STP.