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## How do you calculate moles consumed?

**Divide Grams by Grams per Mole**

**Divide the number of grams of each reactant by the number of grams per mole** for that reactant. 50.0 g of Na are used in this reaction, and there are 22.990 g/mol. 50.0 ÷ 22.990 = 2.1749.

## How many moles of oxygen are required?

**3 moles** of oxygen gas are required.

## How do you calculate the mass of oxygen consumed?

**(3) Use the mole ratios to calculate the mass of O _{2} consumed and MgO produced as shown below:**

- mass O
_{2}= moles(O_{2}) × molar mass(O_{2}) (a) Calculate moles(Mg) = mass(Mg) ÷ molar mass(Mg) moles(Mg) = 12.2 ÷ 24.31 = 0.50 mol. … - mass MgO = moles(MgO) × molar mass(MgO) (a) Calculate moles Mg. moles(Mg) = mass(Mg) ÷ molar mass(Mg)

## How many moles of water are produced when 5 moles of oxygen are consumed?

1 Expert Answer

Then, there are **2 moles** of water produced every time that 5 moles of oxygen react with 2 moles of acetylene.

## What is the mole ratio?

Mole Ratio: is **a conversion factor between compounds in a chemical reaction**, that is derived from the coefficients of the compounds in a balanced equation. The mole ratio is therefore used to convert between quantities of compounds in a chemical reaction.

## How many molecules are in a mole?

The mole is represented by Avogadro’s number, which is **6.022×10 ^{23} atoms** or molecules per mol.

## How do you find the mass of 0.1 mole of KNO3?

Therefore, mass of 0.1 mole of KNO3 is **10.10 g**.

## When 12 moles of O2 reacts with 6 moles of c10h8 What is the limiting reactant 1 c10h8 12 O2 –> 10 co2 4 h2o?

Explanation: it is so bcz 1 mole of C10H8O must requires 12 moles of o2 so 6 moles must require 6*12 which is 72 moles. so **o2** is limiting reagant.