# You asked: How many moles of oxygen are consumed?

Contents

## How do you calculate moles consumed?

Divide Grams by Grams per Mole

Divide the number of grams of each reactant by the number of grams per mole for that reactant. 50.0 g of Na are used in this reaction, and there are 22.990 g/mol. 50.0 ÷ 22.990 = 2.1749.

## How many moles of oxygen are required?

3 moles of oxygen gas are required.

## How do you calculate the mass of oxygen consumed?

(3) Use the mole ratios to calculate the mass of O2 consumed and MgO produced as shown below:

1. mass O2 = moles(O2) × molar mass(O2) (a) Calculate moles(Mg) = mass(Mg) ÷ molar mass(Mg) moles(Mg) = 12.2 ÷ 24.31 = 0.50 mol. …
2. mass MgO = moles(MgO) × molar mass(MgO) (a) Calculate moles Mg. moles(Mg) = mass(Mg) ÷ molar mass(Mg)

## How many moles of water are produced when 5 moles of oxygen are consumed?

Then, there are 2 moles of water produced every time that 5 moles of oxygen react with 2 moles of acetylene.

## What is the mole ratio?

Mole Ratio: is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation. The mole ratio is therefore used to convert between quantities of compounds in a chemical reaction.

THIS IS IMPORTANT:  Does sunscreen make perioral dermatitis worse?

## How many molecules are in a mole?

The mole is represented by Avogadro’s number, which is 6.022×1023 atoms or molecules per mol.

## How do you find the mass of 0.1 mole of KNO3?

Therefore, mass of 0.1 mole of KNO3 is 10.10 g.

## When 12 moles of O2 reacts with 6 moles of c10h8 What is the limiting reactant 1 c10h8 12 O2 –> 10 co2 4 h2o?

Explanation: it is so bcz 1 mole of C10H8O must requires 12 moles of o2 so 6 moles must require 6*12 which is 72 moles. so o2 is limiting reagant.