How many moles are in magnesium phosphate?
Hint:Magnesium phosphate has 3 moles of magnesium, two moles of phosphorus and eight moles of oxygen atom in its chemical formula. Because there are three magnesium atoms, two phosphorus atoms and eight oxygen atoms in magnesium phosphate molecules.
How many moles are in magnesium?
The relative masses of each element can be found on the periodic table. For example, one atom of magnesium weighs 24.31 amu (atomic mass units). However, one mole of magnesium weighs 24.31 g. (Moles were planned that way!)
How many moles of phosphorus are present in one mole of magnesium phosphate?
Notice how we were able to do a multiple comparison between our big compounds and just our phosphorus. We just said that for every one mole of our magnesium phosphate, we do have two moles of phosphorus inside of that.
How do I calculate moles?
So in order to calculate the number of moles of any substance present in the sample, we simply divide the given weight of the substance by its molar mass. Where ‘n’ is the number of moles, ‘m’ is the given mass and ‘M’ is the molar mass.
How many moles are in Mg3 PO4 2?
1 mole of Mg3(PO4)2 (molecule) contains 3 moles of Mg atoms, 2 moles of P atoms and 2X4 moles of O atoms. = 0.03125 moles.
What is the percentage of phosphorus in magnesium phosphate?
Answer: the percentage of phosphorus in magnesium phosphate is 23.567% .
How many phosphate ions are in mg3 po4 2?
There are two phosphate ions in a molecule of magnesium phosphate.
How many moles are there in 48 grams of magnesium?
Here, we are given 48 g of Mg, therefore it is the given mass. Now, coming back to the formula to find the number of atoms. Therefore, number of atoms in 48 g of Mg = 2 mol $ times $ $6.022 times {10^{23}}$atoms/mol= [12.04 times {10^{23}}] atoms. Thus, 48 g of Mg is equivalent to $12.04 times {10^{23}}$ atoms.